Find the x and y Intercepts y=7x+2

$y = 7 x + 2$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = 7 x + 2$

Solve the equation.

Rewrite the equation as $7 x + 2 = 0$ .

$7 x + 2 = 0$

Subtract $2$ from both sides of the equation.

$7 x = - 2$

Divide each term in $7 x = - 2$ by $7$ and simplify.

Divide each term in $7 x = - 2$ by $7$ .

$\frac{7 x}{7} = \frac{- 2}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{- 2}{7}$

Divide $x$ by $1$ .

$x = \frac{- 2}{7}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{2}{7}$

x-intercept(s) in point form.

x-intercept(s): $(- \frac{2}{7}, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = 7 (0) + 2$

Solve the equation.

Remove parentheses.

$y = 7 (0) + 2$

Simplify $7 (0) + 2$ .

Multiply $7$ by $0$ .

$y = 0 + 2$

Add $0$ and $2$ .

$y = 2$

y-intercept(s) in point form.

y-intercept(s): $(0, 2)$

Step 3

List the intersections.

x-intercept(s): $(- \frac{2}{7}, 0)$

y-intercept(s): $(0, 2)$

Step 4