Find the x and y Intercepts y=8/(x^2-x-6)

$y = \frac{8}{x^{2} - x - 6}$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \frac{8}{x^{2} - x - 6}$

Solve the equation.

Set the numerator equal to zero.

$8 = 0$

Since $8 \neq 0$ , there are no solutions.

No solution

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

x-intercept(s): $None$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \frac{8}{{(0)}^{2} - (0) - 6}$

Solve the equation.

Remove parentheses.

$y = \frac{8}{0^{2} - (0) - 6}$

Remove parentheses.

$y = \frac{8}{{(0)}^{2} - (0) - 6}$

Simplify $\frac{8}{{(0)}^{2} - (0) - 6}$ .

Simplify the denominator.

Raising $0$ to any positive power yields $0$ .

$y = \frac{8}{0 - (0) - 6}$

Multiply $- 1$ by $0$ .

$y = \frac{8}{0 + 0 - 6}$

Add $0$ and $0$ .

$y = \frac{8}{0 - 6}$

Subtract $6$ from $0$ .

$y = \frac{8}{- 6}$

Reduce the expression by cancelling the common factors.

Cancel the common factor of $8$ and $- 6$ .

Factor $2$ out of $8$ .

$y = \frac{2 (4)}{- 6}$

Cancel the common factors.

Factor $2$ out of $- 6$ .

$y = \frac{2 \cdot 4}{2 \cdot - 3}$

Cancel the common factor.

$y = \frac{2 \cdot 4}{2 \cdot - 3}$

Rewrite the expression.

$y = \frac{4}{- 3}$

Move the negative in front of the fraction.

$y = - \frac{4}{3}$

y-intercept(s) in point form.

y-intercept(s): $(0, - \frac{4}{3})$

List the intersections.

x-intercept(s): $None$

y-intercept(s): $(0, - \frac{4}{3})$

Find the x and y Intercepts y=8/(x^2-x-6)

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