Find the x and y Intercepts y+9=-3x

$y + 9 = - 3 x$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$(0) + 9 = - 3 x$

Solve the equation.

Rewrite the equation as $- 3 x = (0) + 9$ .

$- 3 x = (0) + 9$

Add $0$ and $9$ .

$- 3 x = 9$

Divide each term in $- 3 x = 9$ by $- 3$ and simplify.

Divide each term in $- 3 x = 9$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{9}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{9}{- 3}$

Divide $x$ by $1$ .

$x = \frac{9}{- 3}$

Simplify the right side.

Divide $9$ by $- 3$ .

$x = - 3$

x-intercept(s) in point form.

x-intercept(s): $(- 3, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y + 9 = - 3 \cdot 0$

Solve the equation.

Multiply $- 3$ by $0$ .

$y + 9 = 0$

Subtract $9$ from both sides of the equation.

$y = - 9$

y-intercept(s) in point form.

y-intercept(s): $(0, - 9)$

Step 3

List the intersections.

x-intercept(s): $(- 3, 0)$

y-intercept(s): $(0, - 9)$

Step 4