Find the x and y Intercepts y = log base x of x+3

$y = \log_{x} (x + 3)$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \log_{x} (x + 3)$

Solve the equation.

Rewrite the equation as $\log_{x} (x + 3) = 0$ .

$\log_{x} (x + 3) = 0$

Rewrite $\log_{x} (x + 3) = 0$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$x^{0} = x + 3$

Solve for $x$ .

Anything raised to $0$ is $1$ .

$1 = x + 3$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$x + 3 = 1$

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$x = 1 - 3$

Subtract $3$ from $1$ .

$x = - 2$

Exclude the solutions that do not make $0 = \log_{x} (x + 3)$ true.

$No solution$

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

x-intercept(s): $None$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \log_{0} ((0) + 3)$

Solve the equation.

Remove parentheses.

$y = \log_{0} (0 + 3)$

Remove parentheses.

$y = \log_{0} ((0) + 3)$

Add $0$ and $3$ .

$y = \log_{0} (3)$

y-intercept(s) in point form.

y-intercept(s): $(0, \log_{0} (3))$

List the intersections.

x-intercept(s): $None$

y-intercept(s): $(0, \log_{0} (3))$

Find the x and y Intercepts y = log base x of x+3

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