Find the x and y Intercepts y=x^2-4x+4

$y = x^{2} - 4 x + 4$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = x^{2} - 4 x + 4$

Solve the equation.

Rewrite the equation as $x^{2} - 4 x + 4 = 0$ .

$x^{2} - 4 x + 4 = 0$

Factor using the perfect square rule.

Rewrite $4$ as $2^{2}$ .

$x^{2} - 4 x + 2^{2} = 0$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$4 x = 2 \cdot x \cdot 2$

Rewrite the polynomial.

$x^{2} - 2 \cdot x \cdot 2 + 2^{2} = 0$

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = x$ and $b = 2$ .

${(x - 2)}^{2} = 0$

Set the $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

x-intercept(s) in point form.

x-intercept(s): $(2, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = {(0)}^{2} - 4 \cdot 0 + 4$

Solve the equation.

Remove parentheses.

$y = 0^{2} - 4 \cdot 0 + 4$

Remove parentheses.

$y = {(0)}^{2} - 4 \cdot 0 + 4$

Simplify ${(0)}^{2} - 4 \cdot 0 + 4$ .

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$y = 0 - 4 \cdot 0 + 4$

Multiply $- 4$ by $0$ .

$y = 0 + 0 + 4$

Simplify by adding numbers.

Add $0$ and $0$ .

$y = 0 + 4$

Add $0$ and $4$ .

$y = 4$

y-intercept(s) in point form.

y-intercept(s): $(0, 4)$

Step 3

List the intersections.

x-intercept(s): $(2, 0)$

y-intercept(s): $(0, 4)$

Step 4

Find the x and y Intercepts y=x^2-4x+4

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