Find the x and y Intercepts y=(x-4)^2

$y = {(x - 4)}^{2}$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = {(x - 4)}^{2}$

Solve the equation.

Rewrite the equation as ${(x - 4)}^{2} = 0$ .

${(x - 4)}^{2} = 0$

Set the $x - 4$ equal to $0$ .

$x - 4 = 0$

Add $4$ to both sides of the equation.

$x = 4$

x-intercept(s) in point form.

x-intercept(s): $(4, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = {((0) - 4)}^{2}$

Solve the equation.

Remove parentheses.

$y = {(0 - 4)}^{2}$

Remove parentheses.

$y = {((0) - 4)}^{2}$

Simplify ${((0) - 4)}^{2}$ .

Subtract $4$ from $0$ .

$y = {(- 4)}^{2}$

Raise $- 4$ to the power of $2$ .

$y = 16$

y-intercept(s) in point form.

y-intercept(s): $(0, 16)$

List the intersections.

x-intercept(s): $(4, 0)$

y-intercept(s): $(0, 16)$