Find Three Ordered Pair Solutions 12x-3y=-3

$12 x - 3 y = - 3$

Step 1

Solve the equation for $y$ .

Subtract $12 x$ from both sides of the equation.

$- 3 y = - 3 - 12 x$

Divide each term in $- 3 y = - 3 - 12 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = - 3 - 12 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 3}{- 3} + \frac{- 12 x}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 3}{- 3} + \frac{- 12 x}{- 3}$

Divide $y$ by $1$ .

$y = \frac{- 3}{- 3} + \frac{- 12 x}{- 3}$

Simplify the right side.

Simplify each term.

Divide $- 3$ by $- 3$ .

$y = 1 + \frac{- 12 x}{- 3}$

Cancel the common factor of $- 12$ and $- 3$ .

Factor $- 3$ out of $- 12 x$ .

$y = 1 + \frac{- 3 (4 x)}{- 3}$

Cancel the common factors.

Factor $- 3$ out of $- 3$ .

$y = 1 + \frac{- 3 (4 x)}{- 3 (1)}$

Cancel the common factor.

$y = 1 + \frac{- 3 (4 x)}{- 3 \cdot 1}$

Rewrite the expression.

$y = 1 + \frac{4 x}{1}$

Divide $4 x$ by $1$ .

$y = 1 + 4 x$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 1 + 4 (0)$

Simplify $1 + 4 (0)$ .

Multiply $4$ by $0$ .

$y = 1 + 0$

Add $1$ and $0$ .

$y = 1$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 1)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 1 + 4 (1)$

Simplify $1 + 4 (1)$ .

Multiply $4$ by $1$ .

$y = 1 + 4$

Add $1$ and $4$ .

$y = 5$

Use the $x$ and $y$ values to form the ordered pair.

$(1, 5)$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 1 + 4 (2)$

Simplify $1 + 4 (2)$ .

Multiply $4$ by $2$ .

$y = 1 + 8$

Add $1$ and $8$ .

$y = 9$

Use the $x$ and $y$ values to form the ordered pair.

$(2, 9)$

Step 6

These are three possible solutions to the equation.

$(0, 1), (1, 5), (2, 9)$

Step 7

Find Three Ordered Pair Solutions 12x-3y=-3

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