Find Three Ordered Pair Solutions -2x-y=-8

$- 2 x - y = - 8$

Step 1

Solve the equation for $y$ .

Add $2 x$ to both sides of the equation.

$- y = - 8 + 2 x$

Divide each term in $- y = - 8 + 2 x$ by $- 1$ and simplify.

Divide each term in $- y = - 8 + 2 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 8}{- 1} + \frac{2 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 8}{- 1} + \frac{2 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 1} + \frac{2 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $- 8$ by $- 1$ .

$y = 8 + \frac{2 x}{- 1}$

Move the negative one from the denominator of $\frac{2 x}{- 1}$ .

$y = 8 - 1 \cdot (2 x)$

Rewrite $- 1 \cdot (2 x)$ as $- (2 x)$ .

$y = 8 - (2 x)$

Multiply $2$ by $- 1$ .

$y = 8 - 2 x$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 8 - 2 \cdot 0$

Simplify $8 - 2 \cdot 0$ .

Multiply $- 2$ by $0$ .

$y = 8 + 0$

Add $8$ and $0$ .

$y = 8$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 8)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 8 - 2 \cdot 1$

Simplify $8 - 2 \cdot 1$ .

Multiply $- 2$ by $1$ .

$y = 8 - 2$

Subtract $2$ from $8$ .

$y = 6$

Use the $x$ and $y$ values to form the ordered pair.

$(1, 6)$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 8 - 2 \cdot 2$

Simplify $8 - 2 \cdot 2$ .

Multiply $- 2$ by $2$ .

$y = 8 - 4$

Subtract $4$ from $8$ .

$y = 4$

Use the $x$ and $y$ values to form the ordered pair.

$(2, 4)$

Step 6

These are three possible solutions to the equation.

$(0, 8), (1, 6), (2, 4)$

Step 7

Find Three Ordered Pair Solutions -2x-y=-8

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