Find Three Ordered Pair Solutions 2y+2=0

$2 y + 2 = 0$

Step 1

Solve the equation for $y$ .

Subtract $2$ from both sides of the equation.

$2 y = - 2$

Divide each term in $2 y = - 2$ by $2$ and simplify.

Divide each term in $2 y = - 2$ by $2$ .

$\frac{2 y}{2} = \frac{- 2}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{- 2}{2}$

Divide $y$ by $1$ .

$y = \frac{- 2}{2}$

Simplify the right side.

Divide $- 2$ by $2$ .

$y = - 1$

Step 2

Since $y = - 1$ is a horizontal line, the y-values are $- 1$ for any value of x. Choose any three x-values to obtain three solutions.

$(0, - 1), (1, - 1), (2, - 1)$

Step 3