Find Three Ordered Pair Solutions 3y+15=0

$3 y + 15 = 0$

Step 1

Solve the equation for $y$ .

Subtract $15$ from both sides of the equation.

$3 y = - 15$

Divide each term in $3 y = - 15$ by $3$ and simplify.

Divide each term in $3 y = - 15$ by $3$ .

$\frac{3 y}{3} = \frac{- 15}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{- 15}{3}$

Divide $y$ by $1$ .

$y = \frac{- 15}{3}$

Simplify the right side.

Divide $- 15$ by $3$ .

$y = - 5$

Step 2

Since $y = - 5$ is a horizontal line, the y-values are $- 5$ for any value of x. Choose any three x-values to obtain three solutions.

$(0, - 5), (1, - 5), (2, - 5)$

Step 3