Find Three Ordered Pair Solutions 3y=3

$3 y = 3$

Step 1

Divide each term in $3 y = 3$ by $3$ and simplify.

Divide each term in $3 y = 3$ by $3$ .

$\frac{3 y}{3} = \frac{3}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{3}{3}$

Divide $y$ by $1$ .

$y = \frac{3}{3}$

Simplify the right side.

Divide $3$ by $3$ .

$y = 1$

Step 2

Since $y = 1$ is a horizontal line, the y-values are $1$ for any value of x. Choose any three x-values to obtain three solutions.

$(0, 1), (1, 1), (2, 1)$

Step 3