Find Three Ordered Pair Solutions 3y=7

$3 y = 7$

Step 1

Divide each term in $3 y = 7$ by $3$ and simplify.

Divide each term in $3 y = 7$ by $3$ .

$\frac{3 y}{3} = \frac{7}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{7}{3}$

Divide $y$ by $1$ .

$y = \frac{7}{3}$

Step 2

Since $y = \frac{7}{3}$ is a horizontal line, the y-values are $\frac{7}{3}$ for any value of x. Choose any three x-values to obtain three solutions.

$(0, \frac{7}{3}), (1, \frac{7}{3}), (2, \frac{7}{3})$

Step 3