Find Three Ordered Pair Solutions 4x+8y=0

$4 x + 8 y = 0$

Step 1

Solve the equation for $y$ .

Subtract $4 x$ from both sides of the equation.

$8 y = - 4 x$

Divide each term in $8 y = - 4 x$ by $8$ and simplify.

Divide each term in $8 y = - 4 x$ by $8$ .

$\frac{8 y}{8} = \frac{- 4 x}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 y}{8} = \frac{- 4 x}{8}$

Divide $y$ by $1$ .

$y = \frac{- 4 x}{8}$

Simplify the right side.

Cancel the common factor of $- 4$ and $8$ .

Factor $4$ out of $- 4 x$ .

$y = \frac{4 (- x)}{8}$

Cancel the common factors.

Factor $4$ out of $8$ .

$y = \frac{4 (- x)}{4 (2)}$

Cancel the common factor.

$y = \frac{4 (- x)}{4 \cdot 2}$

Rewrite the expression.

$y = \frac{- x}{2}$

Move the negative in front of the fraction.

$y = - \frac{x}{2}$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - \frac{0}{2}$

Simplify $- \frac{0}{2}$ .

Divide $0$ by $2$ .

$y = - 0$

Multiply $- 1$ by $0$ .

$y = 0$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 0)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - \frac{1}{2}$

Use the $x$ and $y$ values to form the ordered pair.

$(1, - \frac{1}{2})$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - \frac{2}{2}$

Simplify $- \frac{2}{2}$ .

Cancel the common factor of $2$ .

Cancel the common factor.

$y = - \frac{2}{2}$

Rewrite the expression.

$y = - 1 \cdot 1$

Multiply $- 1$ by $1$ .

$y = - 1$

Use the $x$ and $y$ values to form the ordered pair.

$(2, - 1)$

Step 6

These are three possible solutions to the equation.

$(0, 0), (1, - \frac{1}{2}), (2, - 1)$

Step 7

Find Three Ordered Pair Solutions 4x+8y=0

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