Find Three Ordered Pair Solutions 4x-y=10

$4 x - y = 10$

Step 1

Solve the equation for $y$ .

Subtract $4 x$ from both sides of the equation.

$- y = 10 - 4 x$

Divide each term in $- y = 10 - 4 x$ by $- 1$ and simplify.

Divide each term in $- y = 10 - 4 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{10}{- 1} + \frac{- 4 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{10}{- 1} + \frac{- 4 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{10}{- 1} + \frac{- 4 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $10$ by $- 1$ .

$y = - 10 + \frac{- 4 x}{- 1}$

Move the negative one from the denominator of $\frac{- 4 x}{- 1}$ .

$y = - 10 - 1 \cdot (- 4 x)$

Rewrite $- 1 \cdot (- 4 x)$ as $- (- 4 x)$ .

$y = - 10 - (- 4 x)$

Multiply $- 4$ by $- 1$ .

$y = - 10 + 4 x$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - 10 + 4 (0)$

Simplify $- 10 + 4 (0)$ .

Multiply $4$ by $0$ .

$y = - 10 + 0$

Add $- 10$ and $0$ .

$y = - 10$

Use the $x$ and $y$ values to form the ordered pair.

$(0, - 10)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - 10 + 4 (1)$

Simplify $- 10 + 4 (1)$ .

Multiply $4$ by $1$ .

$y = - 10 + 4$

Add $- 10$ and $4$ .

$y = - 6$

Use the $x$ and $y$ values to form the ordered pair.

$(1, - 6)$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - 10 + 4 (2)$

Simplify $- 10 + 4 (2)$ .

Multiply $4$ by $2$ .

$y = - 10 + 8$

Add $- 10$ and $8$ .

$y = - 2$

Use the $x$ and $y$ values to form the ordered pair.

$(2, - 2)$

Step 6

These are three possible solutions to the equation.

$(0, - 10), (1, - 6), (2, - 2)$

Step 7

Find Three Ordered Pair Solutions 4x-y=10

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