Find Three Ordered Pair Solutions 4x=-y+2

$4 x = - y + 2$

Step 1

Solve the equation for $y$ .

Rewrite the equation as $- y + 2 = 4 x$ .

$- y + 2 = 4 x$

Subtract $2$ from both sides of the equation.

$- y = 4 x - 2$

Divide each term in $- y = 4 x - 2$ by $- 1$ and simplify.

Divide each term in $- y = 4 x - 2$ by $- 1$ .

$\frac{- y}{- 1} = \frac{4 x}{- 1} + \frac{- 2}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{4 x}{- 1} + \frac{- 2}{- 1}$

Divide $y$ by $1$ .

$y = \frac{4 x}{- 1} + \frac{- 2}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{4 x}{- 1}$ .

$y = - 1 \cdot (4 x) + \frac{- 2}{- 1}$

Rewrite $- 1 \cdot (4 x)$ as $- (4 x)$ .

$y = - (4 x) + \frac{- 2}{- 1}$

Multiply $4$ by $- 1$ .

$y = - 4 x + \frac{- 2}{- 1}$

Divide $- 2$ by $- 1$ .

$y = - 4 x + 2$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - 4 \cdot 0 + 2$

Simplify $- 4 \cdot 0 + 2$ .

Multiply $- 4$ by $0$ .

$y = 0 + 2$

Add $0$ and $2$ .

$y = 2$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 2)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - 4 \cdot 1 + 2$

Simplify $- 4 \cdot 1 + 2$ .

Multiply $- 4$ by $1$ .

$y = - 4 + 2$

Add $- 4$ and $2$ .

$y = - 2$

Use the $x$ and $y$ values to form the ordered pair.

$(1, - 2)$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - 4 \cdot 2 + 2$

Simplify $- 4 \cdot 2 + 2$ .

Multiply $- 4$ by $2$ .

$y = - 8 + 2$

Add $- 8$ and $2$ .

$y = - 6$

Use the $x$ and $y$ values to form the ordered pair.

$(2, - 6)$

Step 6

These are three possible solutions to the equation.

$(0, 2), (1, - 2), (2, - 6)$

Step 7

Find Three Ordered Pair Solutions 4x=-y+2

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