Find Three Ordered Pair Solutions -5x-y=-8

$- 5 x - y = - 8$

Step 1

Solve the equation for $y$ .

Add $5 x$ to both sides of the equation.

$- y = - 8 + 5 x$

Divide each term in $- y = - 8 + 5 x$ by $- 1$ and simplify.

Divide each term in $- y = - 8 + 5 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 8}{- 1} + \frac{5 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 8}{- 1} + \frac{5 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 1} + \frac{5 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $- 8$ by $- 1$ .

$y = 8 + \frac{5 x}{- 1}$

Move the negative one from the denominator of $\frac{5 x}{- 1}$ .

$y = 8 - 1 \cdot (5 x)$

Rewrite $- 1 \cdot (5 x)$ as $- (5 x)$ .

$y = 8 - (5 x)$

Multiply $5$ by $- 1$ .

$y = 8 - 5 x$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 8 - 5 \cdot 0$

Simplify $8 - 5 \cdot 0$ .

Multiply $- 5$ by $0$ .

$y = 8 + 0$

Add $8$ and $0$ .

$y = 8$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 8)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 8 - 5 \cdot 1$

Simplify $8 - 5 \cdot 1$ .

Multiply $- 5$ by $1$ .

$y = 8 - 5$

Subtract $5$ from $8$ .

$y = 3$

Use the $x$ and $y$ values to form the ordered pair.

$(1, 3)$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 8 - 5 \cdot 2$

Simplify $8 - 5 \cdot 2$ .

Multiply $- 5$ by $2$ .

$y = 8 - 10$

Subtract $10$ from $8$ .

$y = - 2$

Use the $x$ and $y$ values to form the ordered pair.

$(2, - 2)$

Step 6

These are three possible solutions to the equation.

$(0, 8), (1, 3), (2, - 2)$

Step 7

Find Three Ordered Pair Solutions -5x-y=-8

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