Find Three Ordered Pair Solutions A(n)=-5*2^(x-1)

$A (n) = - 5 \cdot 2^{x - 1}$

Step 1

Write $A (n) = - 5 \cdot 2^{x - 1}$ as an equation.

$y = - 5 \cdot 2^{x - 1}$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Simplify $- 5 \cdot 2^{(0) - 1}$ .

Subtract $1$ from $0$ .

$y = - 5 \cdot 2^{- 1}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$y = - 5 \cdot \frac{1}{2}$

Combine $- 5$ and $\frac{1}{2}$ .

$y = \frac{- 5}{2}$

Move the negative in front of the fraction.

$y = - \frac{5}{2}$

Use the $x$ and $y$ values to form the ordered pair.

$(0, - \frac{5}{2})$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Simplify $- 5 \cdot 2^{(1) - 1}$ .

Subtract $1$ from $1$ .

$y = - 5 \cdot 2^{0}$

Anything raised to $0$ is $1$ .

$y = - 5 \cdot 1$

Multiply $- 5$ by $1$ .

$y = - 5$

Use the $x$ and $y$ values to form the ordered pair.

$(1, - 5)$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Simplify $- 5 \cdot 2^{(2) - 1}$ .

Subtract $1$ from $2$ .

$y = - 5 \cdot 2^{1}$

Evaluate the exponent.

$y = - 5 \cdot 2$

Multiply $- 5$ by $2$ .

$y = - 10$

Use the $x$ and $y$ values to form the ordered pair.

$(2, - 10)$

Step 6

These are three possible solutions to the equation.

$(0, - \frac{5}{2}), (1, - 5), (2, - 10)$

Step 7