Find Three Ordered Pair Solutions f(x) = log base 2 of x+3+2

$f (x) = \log_{2} (x + 3) + 2$

Step 1

Write $f (x) = \log_{2} (x + 3) + 2$ as an equation.

$y = \log_{2} (x + 3) + 2$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = \log_{2} (0 + 3) + 2$

Remove parentheses.

$y = \log_{2} ((0) + 3) + 2$

Add $0$ and $3$ .

$y = \log_{2} (3) + 2$

Use the $x$ and $y$ values to form the ordered pair.

$(0, \log_{2} (3) + 2)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = \log_{2} (1 + 3) + 2$

Remove parentheses.

$y = \log_{2} ((1) + 3) + 2$

Simplify $\log_{2} ((1) + 3) + 2$ .

Simplify each term.

Add $1$ and $3$ .

$y = \log_{2} (4) + 2$

Logarithm base $2$ of $4$ is $2$ .

$y = 2 + 2$

Add $2$ and $2$ .

$y = 4$

Use the $x$ and $y$ values to form the ordered pair.

$(1, 4)$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = \log_{2} (2 + 3) + 2$

Remove parentheses.

$y = \log_{2} ((2) + 3) + 2$

Add $2$ and $3$ .

$y = \log_{2} (5) + 2$

Use the $x$ and $y$ values to form the ordered pair.

$(2, \log_{2} (5) + 2)$

Step 6

These are three possible solutions to the equation.

$(0, \log_{2} (3) + 2), (1, 4), (2, \log_{2} (5) + 2)$

Step 7

Find Three Ordered Pair Solutions f(x) = log base 2 of x+3+2

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