Find Three Ordered Pair Solutions k(x)=4f(x)-2

$k (x) = 4 f (x) - 2$

Step 1

Write $k (x) = 4 f (x) - 2$ as an equation.

$y = 4 f (x) - 2$

Step 2

Multiply $4 f$ by $x$ .

$y = 4 f x - 2$

Step 3

Choose any values for $x$ and $y$ that are in the domain to plug into the equation.

Step 4

Choose $0$ to substitute in for $x$ and $1$ to substitute for $z$ .

Multiply $4 f$ by $0$ .

$y = 4 f \cdot 0 - 2$

Remove parentheses.

$y = 4 f (0) - 2$

Simplify $4 f (0) - 2$ .

Multiply $4 f (0)$ .

Multiply $0$ by $4$ .

$y = 0 f - 2$

Multiply $0$ by $f$ .

$y = 0 - 2$

Subtract $2$ from $0$ .

$y = - 2$

Use the $x$ , $y$ , and $z$ values to form the ordered pair.

$(0, - 2, 1)$

Step 5

Choose $1$ to substitute in for $x$ and $2$ to substitute for $z$ .

Multiply $4 f$ by $1$ .

$y = 4 f \cdot 1 - 2$

Remove parentheses.

$y = 4 f (1) - 2$

Multiply $4$ by $1$ .

$y = 4 f - 2$

Use the $x$ , $y$ , and $z$ values to form the ordered pair.

$(1, 4 f - 2, 2)$

Step 6

Choose $2$ to substitute in for $x$ and $3$ to substitute for $z$ .

Multiply $4 f$ by $2$ .

$y = 4 f \cdot 2 - 2$

Remove parentheses.

$y = 4 f (2) - 2$

Multiply $2$ by $4$ .

$y = 8 f - 2$

Use the $x$ , $y$ , and $z$ values to form the ordered pair.

$(2, 8 f - 2, 3)$

Step 7

These are three possible solutions to the equation.

$(0, - 2, 1), (1, 4 f - 2, 2), (2, 8 f - 2, 3)$

Find Three Ordered Pair Solutions k(x)=4f(x)-2

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