Find Three Ordered Pair Solutions x+y=z

$x + y = z$

Step 1

Subtract $x$ from both sides of the equation.

$y = z - x$

Step 2

Choose any values for $x$ and $y$ that are in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ and $1$ to substitute for $z$ .

Remove parentheses.

$y = 1 - (0)$

Remove parentheses.

$y = (1) - (0)$

Subtract $0$ from $1$ .

$y = 1$

Use the $x$ , $y$ , and $z$ values to form the ordered pair.

$(0, 1, 1)$

Step 4

Choose $1$ to substitute in for $x$ and $2$ to substitute for $z$ .

Remove parentheses.

$y = 2 - (1)$

Remove parentheses.

$y = (2) - (1)$

Simplify $(2) - (1)$ .

Multiply $- 1$ by $1$ .

$y = 2 - 1$

Subtract $1$ from $2$ .

$y = 1$

Use the $x$ , $y$ , and $z$ values to form the ordered pair.

$(1, 1, 2)$

Step 5

Choose $2$ to substitute in for $x$ and $3$ to substitute for $z$ .

Remove parentheses.

$y = 3 - (2)$

Remove parentheses.

$y = (3) - (2)$

Simplify $(3) - (2)$ .

Multiply $- 1$ by $2$ .

$y = 3 - 2$

Subtract $2$ from $3$ .

$y = 1$

Use the $x$ , $y$ , and $z$ values to form the ordered pair.

$(2, 1, 3)$

Step 6

These are three possible solutions to the equation.

$(0, 1, 1), (1, 1, 2), (2, 1, 3)$