Find Three Ordered Pair Solutions y=2x^2

$y = 2 x^{2}$

Step 1

Choose any value for $x$ that is in the domain to plug into the equation.

Step 2

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 2 \cdot 0^{2}$

Remove parentheses.

$y = 2 {(0)}^{2}$

Simplify $2 {(0)}^{2}$ .

Raising $0$ to any positive power yields $0$ .

$y = 2 \cdot 0$

Multiply $2$ by $0$ .

$y = 0$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 0)$

Step 3

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 2 \cdot 1^{2}$

Remove parentheses.

$y = 2 {(1)}^{2}$

Simplify $2 {(1)}^{2}$ .

One to any power is one.

$y = 2 \cdot 1$

Multiply $2$ by $1$ .

$y = 2$

Use the $x$ and $y$ values to form the ordered pair.

$(1, 2)$

Step 4

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 2 \cdot 2^{2}$

Remove parentheses.

$y = 2 {(2)}^{2}$

Simplify $2 {(2)}^{2}$ .

Multiply $2$ by ${(2)}^{2}$ by adding the exponents.

Multiply $2$ by ${(2)}^{2}$ .

Raise $2$ to the power of $1$ .

$y = 2^{1} {(2)}^{2}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y = 2^{1 + 2}$

Add $1$ and $2$ .

$y = 2^{3}$

Raise $2$ to the power of $3$ .

$y = 8$

Use the $x$ and $y$ values to form the ordered pair.

$(2, 8)$

Step 5

These are three possible solutions to the equation.

$(0, 0), (1, 2), (2, 8)$

Step 6

Find Three Ordered Pair Solutions y=2x^2

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