Find Three Ordered Pair Solutions y=4 square root of x-3

$y = 4 \sqrt{x} - 3$

Step 1

Choose any value for $x$ that is in the domain to plug into the equation.

Step 2

Choose $0$ to substitute in for $x$ to find the ordered pair.

Simplify $4 \sqrt{0} - 3$ .

Remove parentheses.

$y = 4 \sqrt{0} - 3$

Simplify each term.

Rewrite $0$ as $0^{2}$ .

$y = 4 \sqrt{0^{2}} - 3$

Pull terms out from under the radical, assuming positive real numbers.

$y = 4 \cdot 0 - 3$

Multiply $4$ by $0$ .

$y = 0 - 3$

Subtract $3$ from $0$ .

$y = - 3$

Use the $x$ and $y$ values to form the ordered pair.

$(0, - 3)$

Step 3

Choose $1$ to substitute in for $x$ to find the ordered pair.

Simplify $4 \sqrt{1} - 3$ .

Remove parentheses.

$y = 4 \sqrt{1} - 3$

Simplify each term.

Any root of $1$ is $1$ .

$y = 4 \cdot 1 - 3$

Multiply $4$ by $1$ .

$y = 4 - 3$

Subtract $3$ from $4$ .

$y = 1$

Use the $x$ and $y$ values to form the ordered pair.

$(1, 1)$

Step 4

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 4 \sqrt{2} - 3$

Use the $x$ and $y$ values to form the ordered pair.

$(2, 4 \sqrt{2} - 3)$

Step 5

These are three possible solutions to the equation.

$(0, - 3), (1, 1), (2, 4 \sqrt{2} - 3)$

Step 6