Find Three Ordered Pair Solutions y=-4x^2+4x-3

$y = - 4 x^{2} + 4 x - 3$

Step 1

Choose any value for $x$ that is in the domain to plug into the equation.

Step 2

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - 4 \cdot 0^{2} + 4 (0) - 3$

Remove parentheses.

$y = - 4 {(0)}^{2} + 4 (0) - 3$

Simplify $- 4 {(0)}^{2} + 4 (0) - 3$ .

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$y = - 4 \cdot 0 + 4 (0) - 3$

Multiply $- 4$ by $0$ .

$y = 0 + 4 (0) - 3$

Multiply $4$ by $0$ .

$y = 0 + 0 - 3$

Simplify by adding and subtracting.

Add $0$ and $0$ .

$y = 0 - 3$

Subtract $3$ from $0$ .

$y = - 3$

Use the $x$ and $y$ values to form the ordered pair.

$(0, - 3)$

Step 3

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - 4 \cdot 1^{2} + 4 (1) - 3$

Remove parentheses.

$y = - 4 {(1)}^{2} + 4 (1) - 3$

Simplify $- 4 {(1)}^{2} + 4 (1) - 3$ .

Simplify each term.

One to any power is one.

$y = - 4 \cdot 1 + 4 (1) - 3$

Multiply $- 4$ by $1$ .

$y = - 4 + 4 (1) - 3$

Multiply $4$ by $1$ .

$y = - 4 + 4 - 3$

Simplify by adding and subtracting.

Add $- 4$ and $4$ .

$y = 0 - 3$

Subtract $3$ from $0$ .

$y = - 3$

Use the $x$ and $y$ values to form the ordered pair.

$(1, - 3)$

Step 4

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = - 4 \cdot 2^{2} + 4 (2) - 3$

Remove parentheses.

$y = - 4 {(2)}^{2} + 4 (2) - 3$

Simplify $- 4 {(2)}^{2} + 4 (2) - 3$ .

Simplify each term.

Raise $2$ to the power of $2$ .

$y = - 4 \cdot 4 + 4 (2) - 3$

Multiply $- 4$ by $4$ .

$y = - 16 + 4 (2) - 3$

Multiply $4$ by $2$ .

$y = - 16 + 8 - 3$

Simplify by adding and subtracting.

Add $- 16$ and $8$ .

$y = - 8 - 3$

Subtract $3$ from $- 8$ .

$y = - 11$

Use the $x$ and $y$ values to form the ordered pair.

$(2, - 11)$

Step 5

These are three possible solutions to the equation.

$(0, - 3), (1, - 3), (2, - 11)$

Step 6

Find Three Ordered Pair Solutions y=-4x^2+4x-3

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