Find Three Ordered Pair Solutions y=5/7x+6

$y = \frac{5}{7} x + 6$

Step 1

Combine $\frac{5}{7}$ and $x$ .

$y = \frac{5 x}{7} + 6$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = \frac{5 (0)}{7} + 6$

Simplify $\frac{5 (0)}{7} + 6$ .

Multiply $5$ by $0$ .

$y = \frac{0}{7} + 6$

Divide $0$ by $7$ .

$y = 0 + 6$

Add $0$ and $6$ .

$y = 6$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 6)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = \frac{5 (1)}{7} + 6$

Simplify $\frac{5 (1)}{7} + 6$ .

Multiply $5$ by $1$ .

$y = \frac{5}{7} + 6$

To write $6$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$y = \frac{5}{7} + 6 \cdot \frac{7}{7}$

Combine $6$ and $\frac{7}{7}$ .

$y = \frac{5}{7} + \frac{6 \cdot 7}{7}$

Combine the numerators over the common denominator.

$y = \frac{5 + 6 \cdot 7}{7}$

Simplify the numerator.

Multiply $6$ by $7$ .

$y = \frac{5 + 42}{7}$

Add $5$ and $42$ .

$y = \frac{47}{7}$

Use the $x$ and $y$ values to form the ordered pair.

$(1, \frac{47}{7})$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = \frac{5 (2)}{7} + 6$

Simplify $\frac{5 (2)}{7} + 6$ .

Multiply $5$ by $2$ .

$y = \frac{10}{7} + 6$

To write $6$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$y = \frac{10}{7} + 6 \cdot \frac{7}{7}$

Combine $6$ and $\frac{7}{7}$ .

$y = \frac{10}{7} + \frac{6 \cdot 7}{7}$

Combine the numerators over the common denominator.

$y = \frac{10 + 6 \cdot 7}{7}$

Simplify the numerator.

Multiply $6$ by $7$ .

$y = \frac{10 + 42}{7}$

Add $10$ and $42$ .

$y = \frac{52}{7}$

Use the $x$ and $y$ values to form the ordered pair.

$(2, \frac{52}{7})$

Step 6

These are three possible solutions to the equation.

$(0, 6), (1, \frac{47}{7}), (2, \frac{52}{7})$

Step 7

Find Three Ordered Pair Solutions y=5/7x+6

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