Find Three Ordered Pair Solutions y=f(x-3)

$y = f (x - 3)$

Step 1

Simplify $f (x - 3)$ .

Apply the distributive property.

$y = f x + f \cdot - 3$

Move $- 3$ to the left of $f$ .

$y = f x - 3 f$

Step 2

Choose any values for $x$ and $y$ that are in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ and $1$ to substitute for $z$ .

Remove parentheses.

$y = f (0) - 3 f$

Simplify $f (0) - 3 f$ .

Multiply $f$ by $0$ .

$y = 0 - 3 f$

Subtract $3 f$ from $0$ .

$y = - 3 f$

Use the $x$ , $y$ , and $z$ values to form the ordered pair.

$(0, - 3 f, 1)$

Step 4

Choose $1$ to substitute in for $x$ and $2$ to substitute for $z$ .

Remove parentheses.

$y = f (1) - 3 f$

Simplify $f (1) - 3 f$ .

Multiply $f$ by $1$ .

$y = f - 3 f$

Subtract $3 f$ from $f$ .

$y = - 2 f$

Use the $x$ , $y$ , and $z$ values to form the ordered pair.

$(1, - 2 f, 2)$

Step 5

Choose $2$ to substitute in for $x$ and $3$ to substitute for $z$ .

Remove parentheses.

$y = f (2) - 3 f$

Simplify $f (2) - 3 f$ .

Move $2$ to the left of $f$ .

$y = 2 f - 3 f$

Subtract $3 f$ from $2 f$ .

$y = - f$

Use the $x$ , $y$ , and $z$ values to form the ordered pair.

$(2, - f, 3)$

Step 6

These are three possible solutions to the equation.

$(0, - 3 f, 1), (1, - 2 f, 2), (2, - f, 3)$