Find Three Ordered Pair Solutions y = square root of 2x-1+3

$y = \sqrt{2 x - 1} + 3$

Step 1

Choose any value for $x$ that is in the domain to plug into the equation.

Step 2

Choose $0$ to substitute in for $x$ to find the ordered pair.

Simplify $\sqrt{2 (0) - 1} + 3$ .

Simplify each term.

Multiply $2$ by $0$ .

$y = \sqrt{0 - 1} + 3$

Subtract $1$ from $0$ .

$y = \sqrt{- 1} + 3$

Rewrite $\sqrt{- 1}$ as $i$ .

$y = i + 3$

Reorder $i$ and $3$ .

$y = 3 + i$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 3 + i)$

Step 3

Choose $1$ to substitute in for $x$ to find the ordered pair.

Simplify $\sqrt{2 (1) - 1} + 3$ .

Simplify each term.

Multiply $2$ by $1$ .

$y = \sqrt{2 - 1} + 3$

Subtract $1$ from $2$ .

$y = \sqrt{1} + 3$

Any root of $1$ is $1$ .

$y = 1 + 3$

Add $1$ and $3$ .

$y = 4$

Use the $x$ and $y$ values to form the ordered pair.

$(1, 4)$

Step 4

Choose $2$ to substitute in for $x$ to find the ordered pair.

Simplify each term.

Multiply $2$ by $2$ .

$y = \sqrt{4 - 1} + 3$

Subtract $1$ from $4$ .

$y = \sqrt{3} + 3$

Use the $x$ and $y$ values to form the ordered pair.

$(2, \sqrt{3} + 3)$

Step 5

These are three possible solutions to the equation.

$(0, 3 + i), (1, 4), (2, \sqrt{3} + 3)$

Step 6