Find Where Undefined/Discontinuous 1/(x-4)-5/(x+6)=10/(x^2+2x-24)

$\frac{1}{x - 4} - \frac{5}{x + 6} = \frac{10}{x^{2} + 2 x - 24}$

Step 1

Subtract $\frac{10}{x^{2} + 2 x - 24}$ from both sides of the equation.

$\frac{1}{x - 4} - \frac{5}{x + 6} - \frac{10}{x^{2} + 2 x - 24} = 0$

Step 2

Simplify $\frac{1}{x - 4} - \frac{5}{x + 6} - \frac{10}{x^{2} + 2 x - 24}$ .

Factor $x^{2} + 2 x - 24$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 24$ and whose sum is $2$ .

$- 4, 6$

Write the factored form using these integers.

$\frac{1}{x - 4} - \frac{5}{x + 6} - \frac{10}{(x - 4) (x + 6)} = 0$

To write $\frac{1}{x - 4}$ as a fraction with a common denominator, multiply by $\frac{x + 6}{x + 6}$ .

$\frac{1}{x - 4} \cdot \frac{x + 6}{x + 6} - \frac{5}{x + 6} - \frac{10}{(x - 4) (x + 6)} = 0$

To write $- \frac{5}{x + 6}$ as a fraction with a common denominator, multiply by $\frac{x - 4}{x - 4}$ .

$\frac{1}{x - 4} \cdot \frac{x + 6}{x + 6} - \frac{5}{x + 6} \cdot \frac{x - 4}{x - 4} - \frac{10}{(x - 4) (x + 6)} = 0$

Write each expression with a common denominator of $(x - 4) (x + 6)$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{1}{x - 4}$ by $\frac{x + 6}{x + 6}$ .

$\frac{x + 6}{(x - 4) (x + 6)} - \frac{5}{x + 6} \cdot \frac{x - 4}{x - 4} - \frac{10}{(x - 4) (x + 6)} = 0$

Multiply $\frac{5}{x + 6}$ by $\frac{x - 4}{x - 4}$ .

$\frac{x + 6}{(x - 4) (x + 6)} - \frac{5 (x - 4)}{(x + 6) (x - 4)} - \frac{10}{(x - 4) (x + 6)} = 0$

Reorder the factors of $(x - 4) (x + 6)$ .

$\frac{x + 6}{(x + 6) (x - 4)} - \frac{5 (x - 4)}{(x + 6) (x - 4)} - \frac{10}{(x - 4) (x + 6)} = 0$

Combine the numerators over the common denominator.

$\frac{x + 6 - 5 (x - 4)}{(x + 6) (x - 4)} - \frac{10}{(x - 4) (x + 6)} = 0$

Combine the numerators over the common denominator.

$\frac{x + 6 - 5 (x - 4) - 10}{(x + 6) (x - 4)} = 0$

Simplify each term.

Apply the distributive property.

$\frac{x + 6 - 5 x - 5 \cdot - 4 - 10}{(x + 6) (x - 4)} = 0$

Multiply $- 5$ by $- 4$ .

$\frac{x + 6 - 5 x + 20 - 10}{(x + 6) (x - 4)} = 0$

Subtract $5 x$ from $x$ .

$\frac{- 4 x + 6 + 20 - 10}{(x + 6) (x - 4)} = 0$

Add $6$ and $20$ .

$\frac{- 4 x + 26 - 10}{(x + 6) (x - 4)} = 0$

Subtract $10$ from $26$ .

$\frac{- 4 x + 16}{(x + 6) (x - 4)} = 0$

Factor $4$ out of $- 4 x + 16$ .

Factor $4$ out of $- 4 x$ .

$\frac{4 (- x) + 16}{(x + 6) (x - 4)} = 0$

Factor $4$ out of $16$ .

$\frac{4 (- x) + 4 (4)}{(x + 6) (x - 4)} = 0$

Factor $4$ out of $4 (- x) + 4 (4)$ .

$\frac{4 (- x + 4)}{(x + 6) (x - 4)} = 0$

Cancel the common factor of $- x + 4$ and $x - 4$ .

Factor $- 1$ out of $- x$ .

$\frac{4 (- (x) + 4)}{(x + 6) (x - 4)} = 0$

Rewrite $4$ as $- 1 (- 4)$ .

$\frac{4 (- (x) - 1 (- 4))}{(x + 6) (x - 4)} = 0$

Factor $- 1$ out of $- (x) - 1 (- 4)$ .

$\frac{4 (- (x - 4))}{(x + 6) (x - 4)} = 0$

Rewrite $- (x - 4)$ as $- 1 (x - 4)$ .

$\frac{4 (- 1 (x - 4))}{(x + 6) (x - 4)} = 0$

Cancel the common factor.

$\frac{4 (- 1 (x - 4))}{(x + 6) (x - 4)} = 0$

Rewrite the expression.

$\frac{4 \cdot (- 1)}{x + 6} = 0$

Multiply $4$ by $- 1$ .

$\frac{- 4}{x + 6} = 0$

Move the negative in front of the fraction.

$- \frac{4}{x + 6} = 0$

Step 3

Set the denominator in $\frac{4}{x + 6}$ equal to $0$ to find where the expression is undefined.

$x + 6 = 0$

Step 4

Subtract $6$ from both sides of the equation.

$x = - 6$

Step 5

Find Where Undefined/Discontinuous 1/(x-4)-5/(x+6)=10/(x^2+2x-24)

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