Find Where Undefined/Discontinuous (27y^3-1)/(3y-1)

$\frac{27 y^{3} - 1}{3 y - 1}$

Step 1

Set the denominator in $\frac{27 y^{3} - 1}{3 y - 1}$ equal to $0$ to find where the expression is undefined.

$3 y - 1 = 0$

Step 2

Solve for $y$ .

Add $1$ to both sides of the equation.

$3 y = 1$

Divide each term in $3 y = 1$ by $3$ and simplify.

Divide each term in $3 y = 1$ by $3$ .

$\frac{3 y}{3} = \frac{1}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{1}{3}$

Divide $y$ by $1$ .

$y = \frac{1}{3}$

Step 3