Find Where Undefined/Discontinuous (2t+3)/(2t+8)

$\frac{2 t + 3}{2 t + 8}$

Set the denominator in $\frac{2 t + 3}{2 t + 8}$ equal to $0$ to find where the expression is undefined.

$2 t + 8 = 0$

Solve for $t$ .

Subtract $8$ from both sides of the equation.

$2 t = - 8$

Divide each term in $2 t = - 8$ by $2$ and simplify.

Divide each term in $2 t = - 8$ by $2$ .

$\frac{2 t}{2} = \frac{- 8}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 t}{2} = \frac{- 8}{2}$

Divide $t$ by $1$ .

$t = \frac{- 8}{2}$

Simplify the right side.

Divide $- 8$ by $2$ .

$t = - 4$