Find Where Undefined/Discontinuous (3n+12)/(13-4n)

$\frac{3 n + 12}{13 - 4 n}$

Step 1

Set the denominator in $\frac{3 n + 12}{13 - 4 n}$ equal to $0$ to find where the expression is undefined.

$13 - 4 n = 0$

Step 2

Solve for $n$ .

Subtract $13$ from both sides of the equation.

$- 4 n = - 13$

Divide each term in $- 4 n = - 13$ by $- 4$ and simplify.

Divide each term in $- 4 n = - 13$ by $- 4$ .

$\frac{- 4 n}{- 4} = \frac{- 13}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 n}{- 4} = \frac{- 13}{- 4}$

Divide $n$ by $1$ .

$n = \frac{- 13}{- 4}$

Simplify the right side.

Dividing two negative values results in a positive value.

$n = \frac{13}{4}$

Step 3