Find Where Undefined/Discontinuous (-9/(2b^2))÷(15/(-7b^5))

$\frac{- 9}{2 b^{2}} \div \frac{15}{- 7 b^{5}}$

Step 1

Set the denominator in $\frac{- 9}{2 b^{2}}$ equal to $0$ to find where the expression is undefined.

$2 b^{2} = 0$

Step 2

Solve for $b$ .

Divide each term in $2 b^{2} = 0$ by $2$ and simplify.

Divide each term in $2 b^{2} = 0$ by $2$ .

$\frac{2 b^{2}}{2} = \frac{0}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 b^{2}}{2} = \frac{0}{2}$

Divide $b^{2}$ by $1$ .

$b^{2} = \frac{0}{2}$

Simplify the right side.

Divide $0$ by $2$ .

$b^{2} = 0$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$b = \pm \sqrt{0}$

Simplify $\pm \sqrt{0}$ .

Rewrite $0$ as $0^{2}$ .

$b = \pm \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$b = \pm 0$

Plus or minus $0$ is $0$ .

$b = 0$

Step 3

Set the denominator in $\frac{15}{- 7 b^{5}}$ equal to $0$ to find where the expression is undefined.

$- 7 b^{5} = 0$

Step 4

Solve for $b$ .

Divide each term in $- 7 b^{5} = 0$ by $- 7$ and simplify.

Divide each term in $- 7 b^{5} = 0$ by $- 7$ .

$\frac{- 7 b^{5}}{- 7} = \frac{0}{- 7}$

Simplify the left side.

Cancel the common factor of $- 7$ .

Cancel the common factor.

$\frac{- 7 b^{5}}{- 7} = \frac{0}{- 7}$

Divide $b^{5}$ by $1$ .

$b^{5} = \frac{0}{- 7}$

Simplify the right side.

Divide $0$ by $- 7$ .

$b^{5} = 0$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$b = \sqrt[5]{0}$

Simplify $\sqrt[5]{0}$ .

Rewrite $0$ as $0^{5}$ .

$b = \sqrt[5]{0^{5}}$

Pull terms out from under the radical, assuming real numbers.

$b = 0$

Step 5

Set the denominator in $\frac{\frac{- 9}{2 b^{2}}}{\frac{15}{- 7 b^{5}}}$ equal to $0$ to find where the expression is undefined.

$\frac{15}{- 7 b^{5}} = 0$

Step 6

Solve for $b$ .

Set the numerator equal to zero.

$15 = 0$

Since $15 \neq 0$ , there are no solutions.

No solution

Step 7

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$b = 0$

Step 8

Find Where Undefined/Discontinuous (-9/(2b^2))÷(15/(-7b^5))

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