Find Where Undefined/Discontinuous f(x)=(4x^2-4x-8)/(2x+2)

$f (x) = \frac{4 x^{2} - 4 x - 8}{2 x + 2}$

Step 1

Set the denominator in $\frac{4 x^{2} - 4 x - 8}{2 x + 2}$ equal to $0$ to find where the expression is undefined.

$2 x + 2 = 0$

Step 2

Solve for $x$ .

Subtract $2$ from both sides of the equation.

$2 x = - 2$

Divide each term in $2 x = - 2$ by $2$ and simplify.

Divide each term in $2 x = - 2$ by $2$ .

$\frac{2 x}{2} = \frac{- 2}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 2}{2}$

Divide $x$ by $1$ .

$x = \frac{- 2}{2}$

Simplify the right side.

Divide $- 2$ by $2$ .

$x = - 1$

Step 3