Find Where Undefined/Discontinuous f(x)=(9x^2-36)/(3x+6)

$f (x) = \frac{9 x^{2} - 36}{3 x + 6}$

Step 1

Set the denominator in $\frac{9 x^{2} - 36}{3 x + 6}$ equal to $0$ to find where the expression is undefined.

$3 x + 6 = 0$

Step 2

Solve for $x$ .

Subtract $6$ from both sides of the equation.

$3 x = - 6$

Divide each term in $3 x = - 6$ by $3$ and simplify.

Divide each term in $3 x = - 6$ by $3$ .

$\frac{3 x}{3} = \frac{- 6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{- 6}{3}$

Divide $x$ by $1$ .

$x = \frac{- 6}{3}$

Simplify the right side.

Divide $- 6$ by $3$ .

$x = - 2$

Step 3