Find Where Undefined/Discontinuous (n^2)/(-2n+8)

$\frac{n^{2}}{- 2 n + 8}$

Step 1

Set the denominator in $\frac{n^{2}}{- 2 n + 8}$ equal to $0$ to find where the expression is undefined.

$- 2 n + 8 = 0$

Step 2

Solve for $n$ .

Subtract $8$ from both sides of the equation.

$- 2 n = - 8$

Divide each term in $- 2 n = - 8$ by $- 2$ and simplify.

Divide each term in $- 2 n = - 8$ by $- 2$ .

$\frac{- 2 n}{- 2} = \frac{- 8}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 n}{- 2} = \frac{- 8}{- 2}$

Divide $n$ by $1$ .

$n = \frac{- 8}{- 2}$

Simplify the right side.

Divide $- 8$ by $- 2$ .

$n = 4$

Step 3