Find Where Undefined/Discontinuous (x^2-8x+16)/(2x-8)

$\frac{x^{2} - 8 x + 16}{2 x - 8}$

Step 1

Set the denominator in $\frac{x^{2} - 8 x + 16}{2 x - 8}$ equal to $0$ to find where the expression is undefined.

$2 x - 8 = 0$

Step 2

Solve for $x$ .

Add $8$ to both sides of the equation.

$2 x = 8$

Divide each term in $2 x = 8$ by $2$ and simplify.

Divide each term in $2 x = 8$ by $2$ .

$\frac{2 x}{2} = \frac{8}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{8}{2}$

Divide $x$ by $1$ .

$x = \frac{8}{2}$

Simplify the right side.

Divide $8$ by $2$ .

$x = 4$

Step 3