Find Where Undefined/Discontinuous (x-2)/(8x-2)

$\frac{x - 2}{8 x - 2}$

Step 1

Set the denominator in $\frac{x - 2}{8 x - 2}$ equal to $0$ to find where the expression is undefined.

$8 x - 2 = 0$

Step 2

Solve for $x$ .

Add $2$ to both sides of the equation.

$8 x = 2$

Divide each term in $8 x = 2$ by $8$ and simplify.

Divide each term in $8 x = 2$ by $8$ .

$\frac{8 x}{8} = \frac{2}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} = \frac{2}{8}$

Divide $x$ by $1$ .

$x = \frac{2}{8}$

Simplify the right side.

Cancel the common factor of $2$ and $8$ .

Factor $2$ out of $2$ .

$x = \frac{2 (1)}{8}$

Cancel the common factors.

Factor $2$ out of $8$ .

$x = \frac{2 \cdot 1}{2 \cdot 4}$

Cancel the common factor.

$x = \frac{2 \cdot 1}{2 \cdot 4}$

Rewrite the expression.

$x = \frac{1}{4}$

Step 3