Find Where Undefined/Discontinuous (x-4)/(x^2+4x+3)

$\frac{x - 4}{x^{2} + 4 x + 3}$

Step 1

Set the denominator in $\frac{x - 4}{x^{2} + 4 x + 3}$ equal to $0$ to find where the expression is undefined.

$x^{2} + 4 x + 3 = 0$

Step 2

Solve for $x$ .

Factor $x^{2} + 4 x + 3$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $3$ and whose sum is $4$ .

$1, 3$

Write the factored form using these integers.

$(x + 1) (x + 3) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 1 = 0$

$x + 3 = 0$

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

The final solution is all the values that make $(x + 1) (x + 3) = 0$ true.

$x = - 1, - 3$

Step 3

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x = - 3, x = - 1$

Step 4

Find Where Undefined/Discontinuous (x-4)/(x^2+4x+3)

Related Questions

Support LCMGCF.com by disabling your adblocker.