Find Where Undefined/Discontinuous (x-x^2)/(x^2-1)

$\frac{x - x^{2}}{x^{2} - 1}$

Step 1

Set the denominator in $\frac{x - x^{2}}{x^{2} - 1}$ equal to $0$ to find where the expression is undefined.

$x^{2} - 1 = 0$

Step 2

Solve for $x$ .

Add $1$ to both sides of the equation.

$x^{2} = 1$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{1}$

Any root of $1$ is $1$ .

$x = \pm 1$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 1$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 1$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 1, - 1$

Step 3

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x = - 1, x = 1$

Step 4

Find Where Undefined/Discontinuous (x-x^2)/(x^2-1)

Related Questions

Support LCMGCF.com by disabling your adblocker.