Find Where Undefined/Discontinuous ((y^2-64)/y)÷((y+8)/(y-8))

Set the denominator in ${\displaystyle \frac{y^2-64}{y}}$ equal to ${\displaystyle 0}$ to find where the expression is undefined.

Set the denominator in ${\displaystyle \frac{y+8}{y-8}}$ equal to ${\displaystyle 0}$ to find where the expression is undefined.

Add ${\displaystyle 8}$ to both sides of the equation.

Set the denominator in ${\displaystyle \frac{\frac{y^2-64}{y}}{\frac{y+8}{y-8}}}$ equal to ${\displaystyle 0}$ to find where the expression is undefined.

The equation is undefined where the denominator equals ${\displaystyle 0}$, the argument of a square root is less than ${\displaystyle 0}$, or the argument of a logarithm is less than or equal to ${\displaystyle 0}$.