Find Where Undefined/Discontinuous y=((x+2)(x-7))/(x^2-5x-14)

$y = \frac{(x + 2) (x - 7)}{x^{2} - 5 x - 14}$

Step 1

Set the denominator in $\frac{(x + 2) (x - 7)}{x^{2} - 5 x - 14}$ equal to $0$ to find where the expression is undefined.

$x^{2} - 5 x - 14 = 0$

Step 2

Solve for $x$ .

Factor $x^{2} - 5 x - 14$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 14$ and whose sum is $- 5$ .

$- 7, 2$

Write the factored form using these integers.

$(x - 7) (x + 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 7 = 0$

$x + 2 = 0$

Set $x - 7$ equal to $0$ and solve for $x$ .

Set $x - 7$ equal to $0$ .

$x - 7 = 0$

Add $7$ to both sides of the equation.

$x = 7$

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

The final solution is all the values that make $(x - 7) (x + 2) = 0$ true.

$x = 7, - 2$

Step 3

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x = - 2, x = 7$

Step 4

Find Where Undefined/Discontinuous y=((x+2)(x-7))/(x^2-5x-14)

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