Find Where Undefined/Discontinuous (z^2-16z+64)/(z^2-64)

$\frac{z^{2} - 16 z + 64}{z^{2} - 64}$

Step 1

Set the denominator in $\frac{z^{2} - 16 z + 64}{z^{2} - 64}$ equal to $0$ to find where the expression is undefined.

$z^{2} - 64 = 0$

Step 2

Solve for $z$ .

Add $64$ to both sides of the equation.

$z^{2} = 64$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$z = \pm \sqrt{64}$

Simplify $\pm \sqrt{64}$ .

Rewrite $64$ as $8^{2}$ .

$z = \pm \sqrt{8^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$z = \pm 8$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$z = 8$

Next, use the negative value of the $\pm$ to find the second solution.

$z = - 8$

The complete solution is the result of both the positive and negative portions of the solution.

$z = 8, - 8$

Step 3

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$z = - 8, z = 8$

Step 4

Find Where Undefined/Discontinuous (z^2-16z+64)/(z^2-64)

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