Graph 10>=x/3+6

$10 \geq \frac{x}{3} + 6$

Rewrite so $x$ is on the left side of the inequality.

$\frac{x}{3} + 6 \leq 10$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $6$ from both sides of the inequality.

$\frac{x}{3} \leq 10 - 6$

Subtract $6$ from $10$ .

$\frac{x}{3} \leq 4$

Multiply both sides by $3$ .

$\frac{x}{3} \cdot 3 \leq 4 \cdot 3$

Simplify.

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{x}{3} \cdot 3 \leq 4 \cdot 3$

Rewrite the expression.

$x \leq 4 \cdot 3$

Simplify the right side.

Multiply $4$ by $3$ .

$x \leq 12$