Graph 2x-2y=4 -x+y=-2

$2 x - 2 y = 4$ $- x + y = - 2$

Graph $2 x - 2 y = 4$ .

Solve for $y$ .

Subtract $2 x$ from both sides of the equation.

$- 2 y = 4 - 2 x$

Divide each term in $- 2 y = 4 - 2 x$ by $- 2$ and simplify.

Divide each term in $- 2 y = 4 - 2 x$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{4}{- 2} + \frac{- 2 x}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{4}{- 2} + \frac{- 2 x}{- 2}$

Divide $y$ by $1$ .

$y = \frac{4}{- 2} + \frac{- 2 x}{- 2}$

Simplify the right side.

Simplify each term.

Divide $4$ by $- 2$ .

$y = - 2 + \frac{- 2 x}{- 2}$

Cancel the common factor of $- 2$ .

Cancel the common factor.

$y = - 2 + \frac{- 2 x}{- 2}$

Divide $x$ by $1$ .

$y = - 2 + x$

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- 2$ and $x$ .

$y = x - 2$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = - 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, - 2)$

Slope: $1$

y-intercept: $(0, - 2)$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Reorder $- 2$ and $x$ .

$y = x - 2$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & - 2 \\ 1 & - 1 \end{array}$

Graph the line using the slope and the y-intercept, or the points.

Slope: $1$

y-intercept: $(0, - 2)$

$\begin{array}{c} x & y \\ 0 & - 2 \\ 1 & - 1 \end{array}$

Slope: $1$

y-intercept: $(0, - 2)$

$\begin{array}{c} x & y \\ 0 & - 2 \\ 1 & - 1 \end{array}$

Plot each graph on the same coordinate system.

$2 x - 2 y = 4$

$- x + y = - 2$

Graph 2x-2y=4 -x+y=-2

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