Graph 2x-y=0

$2 x - y = 0$

Step 1

Solve for $y$ .

Subtract $2 x$ from both sides of the equation.

$- y = - 2 x$

Divide each term in $- y = - 2 x$ by $- 1$ and simplify.

Divide each term in $- y = - 2 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 2 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 2 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- 2 x}{- 1}$

Simplify the right side.

Move the negative one from the denominator of $\frac{- 2 x}{- 1}$ .

$y = - 1 \cdot (- 2 x)$

Rewrite $- 1 \cdot (- 2 x)$ as $- (- 2 x)$ .

$y = - (- 2 x)$

Multiply $- 2$ by $- 1$ .

$y = 2 x$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 2$

$b = 0$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $2$

y-intercept: $(0, 0)$

Slope: $2$

y-intercept: $(0, 0)$

Step 3

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & 2 \end{array}$

Step 4

Graph the line using the slope and the y-intercept, or the points.

Slope: $2$

y-intercept: $(0, 0)$

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & 2 \end{array}$

Step 5