Graph 3x-1>=y

$3 x - 1 \geq y$

Rewrite so $y$ is on the left side of the inequality.

$y \leq 3 x - 1$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 3$

$b = - 1$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $3$

y-intercept: $(0, - 1)$

Slope: $3$

y-intercept: $(0, - 1)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $3 x - 1$ .

$y \leq 3 x - 1$