Graph 3x-y<=12 2x+y<=10 x>=0 y>=0

$3 x - y \leq 12$ $2 x + y \leq 10$ $x \geq 0$ $y \geq 0$

Graph $3 x - y \leq 12$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $3 x$ from both sides of the inequality.

$- y \leq 12 - 3 x$

Divide each term in $- y \leq 12 - 3 x$ by $- 1$ and simplify.

Divide each term in $- y \leq 12 - 3 x$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} \geq \frac{12}{- 1} + \frac{- 3 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} \geq \frac{12}{- 1} + \frac{- 3 x}{- 1}$

Divide $y$ by $1$ .

$y \geq \frac{12}{- 1} + \frac{- 3 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $12$ by $- 1$ .

$y \geq - 12 + \frac{- 3 x}{- 1}$

Move the negative one from the denominator of $\frac{- 3 x}{- 1}$ .

$y \geq - 12 - 1 \cdot (- 3 x)$

Rewrite $- 1 \cdot (- 3 x)$ as $- (- 3 x)$ .

$y \geq - 12 - (- 3 x)$

Multiply $- 3$ by $- 1$ .

$y \geq - 12 + 3 x$

Rearrange terms.

$y \geq 3 x - 12$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 3$

$b = - 12$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $3$

y-intercept: $(0, - 12)$

Slope: $3$

y-intercept: $(0, - 12)$

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $3 x - 12$ .

$y \geq 3 x - 12$

Graph $2 x + y \leq 10$ .

Write in $y = m x + b$ form.

Subtract $2 x$ from both sides of the inequality.

$y \leq 10 - 2 x$

Rearrange terms.

$y \leq - 2 x + 10$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 2$

$b = 10$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 2$

y-intercept: $(0, 10)$

Slope: $- 2$

y-intercept: $(0, 10)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $- 2 x + 10$ .

$y \leq - 2 x + 10$

Graph $x \geq 0$ .

$x \geq 0$

Graph $y \geq 0$ .

$y \geq 0$

Plot each graph on the same coordinate system.

$3 x - y \leq 12$

$2 x + y \leq 10$

$x \geq 0$

$y \geq 0$

Graph 3x-y<=12 2x+y<=10 x>=0 y>=0

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