Graph 3y-2x=-12

$3 y - 2 x = - 12$

Step 1

Solve for $y$ .

Add $2 x$ to both sides of the equation.

$3 y = - 12 + 2 x$

Divide each term in $3 y = - 12 + 2 x$ by $3$ and simplify.

Divide each term in $3 y = - 12 + 2 x$ by $3$ .

$\frac{3 y}{3} = \frac{- 12}{3} + \frac{2 x}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{- 12}{3} + \frac{2 x}{3}$

Divide $y$ by $1$ .

$y = \frac{- 12}{3} + \frac{2 x}{3}$

Simplify the right side.

Divide $- 12$ by $3$ .

$y = - 4 + \frac{2 x}{3}$

Step 2

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- 4$ and $\frac{2 x}{3}$ .

$y = \frac{2 x}{3} - 4$

Reorder terms.

$y = \frac{2}{3} x - 4$

Step 3

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{2}{3}$

$b = - 4$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{2}{3}$

y-intercept: $(0, - 4)$

Slope: $\frac{2}{3}$

y-intercept: $(0, - 4)$

Step 4

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Write in $y = m x + b$ form.

Reorder $- 4$ and $\frac{2 x}{3}$ .

$y = \frac{2 x}{3} - 4$

Reorder terms.

$y = \frac{2}{3} x - 4$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & - 4 \\ 3 & - 2 \end{array}$

Step 5

Graph the line using the slope and the y-intercept, or the points.

Slope: $\frac{2}{3}$

y-intercept: $(0, - 4)$

$\begin{array}{c} x & y \\ 0 & - 4 \\ 3 & - 2 \end{array}$

Step 6

Graph 3y-2x=-12

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