Graph 4x^2>y-3

$4 x^{2} > y - 3$

Solve for $y$ .

Rewrite so $y$ is on the left side of the inequality.

$y - 3 < 4 x^{2}$

Add $3$ to both sides of the inequality.

$y < 4 x^{2} + 3$

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a dashed line, then shade the area below the boundary line since $y$ is less than $4 x^{2} + 3$ .

$y < 4 x^{2} + 3$