Graph 4x+6y=10

$4 x + 6 y = 10$

Step 1

Solve for $y$ .

Subtract $4 x$ from both sides of the equation.

$6 y = 10 - 4 x$

Divide each term in $6 y = 10 - 4 x$ by $6$ and simplify.

Divide each term in $6 y = 10 - 4 x$ by $6$ .

$\frac{6 y}{6} = \frac{10}{6} + \frac{- 4 x}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 y}{6} = \frac{10}{6} + \frac{- 4 x}{6}$

Divide $y$ by $1$ .

$y = \frac{10}{6} + \frac{- 4 x}{6}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $10$ and $6$ .

Factor $2$ out of $10$ .

$y = \frac{2 (5)}{6} + \frac{- 4 x}{6}$

Cancel the common factors.

Factor $2$ out of $6$ .

$y = \frac{2 \cdot 5}{2 \cdot 3} + \frac{- 4 x}{6}$

Cancel the common factor.

$y = \frac{2 \cdot 5}{2 \cdot 3} + \frac{- 4 x}{6}$

Rewrite the expression.

$y = \frac{5}{3} + \frac{- 4 x}{6}$

Cancel the common factor of $- 4$ and $6$ .

Factor $2$ out of $- 4 x$ .

$y = \frac{5}{3} + \frac{2 (- 2 x)}{6}$

Cancel the common factors.

Factor $2$ out of $6$ .

$y = \frac{5}{3} + \frac{2 (- 2 x)}{2 (3)}$

Cancel the common factor.

$y = \frac{5}{3} + \frac{2 (- 2 x)}{2 \cdot 3}$

Rewrite the expression.

$y = \frac{5}{3} + \frac{- 2 x}{3}$

Move the negative in front of the fraction.

$y = \frac{5}{3} - \frac{2 x}{3}$

Step 2

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $\frac{5}{3}$ and $- \frac{2 x}{3}$ .

$y = - \frac{2 x}{3} + \frac{5}{3}$

Write in $y = m x + b$ form.

Reorder terms.

$y = - (\frac{2}{3} x) + \frac{5}{3}$

Remove parentheses.

$y = - \frac{2}{3} x + \frac{5}{3}$

Step 3

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - \frac{2}{3}$

$b = \frac{5}{3}$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- \frac{2}{3}$

y-intercept: $(0, \frac{5}{3})$

Slope: $- \frac{2}{3}$

y-intercept: $(0, \frac{5}{3})$

Step 4

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Write in $y = m x + b$ form.

Reorder $\frac{5}{3}$ and $- \frac{2 x}{3}$ .

$y = - \frac{2 x}{3} + \frac{5}{3}$

Reorder terms.

$y = - (\frac{2}{3} x) + \frac{5}{3}$

Remove parentheses.

$y = - \frac{2}{3} x + \frac{5}{3}$

Find the x-intercept.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - \frac{2}{3} x + \frac{5}{3}$

Solve the equation.

Rewrite the equation as $- \frac{2}{3} x + \frac{5}{3} = 0$ .

$- \frac{2}{3} x + \frac{5}{3} = 0$

Simplify each term.

Combine $x$ and $\frac{2}{3}$ .

$- \frac{x \cdot 2}{3} + \frac{5}{3} = 0$

Move $2$ to the left of $x$ .

$- \frac{2 x}{3} + \frac{5}{3} = 0$

Subtract $\frac{5}{3}$ from both sides of the equation.

$- \frac{2 x}{3} = - \frac{5}{3}$

Since the expression on each side of the equation has the same denominator, the numerators must be equal.

$- 2 x = - 5$

Divide each term in $- 2 x = - 5$ by $- 2$ and simplify.

Divide each term in $- 2 x = - 5$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 5}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 5}{- 2}$

Divide $x$ by $1$ .

$x = \frac{- 5}{- 2}$

Simplify the right side.

Dividing two negative values results in a positive value.

$x = \frac{5}{2}$

x-intercept(s) in point form.

x-intercept(s): $(\frac{5}{2}, 0)$

Find the y-intercept.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - \frac{2}{3} \cdot 0 + \frac{5}{3}$

Solve the equation.

Remove parentheses.

$y = - \frac{2}{3} \cdot 0 + \frac{5}{3}$

Simplify $- \frac{2}{3} \cdot 0 + \frac{5}{3}$ .

Multiply $- \frac{2}{3} \cdot 0$ .

Multiply $0$ by $- 1$ .

$y = 0 (\frac{2}{3}) + \frac{5}{3}$

Multiply $0$ by $\frac{2}{3}$ .

$y = 0 + \frac{5}{3}$

Add $0$ and $\frac{5}{3}$ .

$y = \frac{5}{3}$

y-intercept(s) in point form.

y-intercept(s): $(0, \frac{5}{3})$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & \frac{5}{3} \\ \frac{5}{2} & 0 \end{array}$

Step 5

Graph the line using the slope and the y-intercept, or the points.

Slope: $- \frac{2}{3}$

y-intercept: $(0, \frac{5}{3})$

$\begin{array}{c} x & y \\ 0 & \frac{5}{3} \\ \frac{5}{2} & 0 \end{array}$

Step 6

Graph 4x+6y=10

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