Graph 4x-y>8

$4 x - y > 8$

Step 1

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $4 x$ from both sides of the inequality.

$- y > 8 - 4 x$

Divide each term in $- y > 8 - 4 x$ by $- 1$ and simplify.

Divide each term in $- y > 8 - 4 x$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} < \frac{8}{- 1} + \frac{- 4 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} < \frac{8}{- 1} + \frac{- 4 x}{- 1}$

Divide $y$ by $1$ .

$y < \frac{8}{- 1} + \frac{- 4 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $8$ by $- 1$ .

$y < - 8 + \frac{- 4 x}{- 1}$

Move the negative one from the denominator of $\frac{- 4 x}{- 1}$ .

$y < - 8 - 1 \cdot (- 4 x)$

Rewrite $- 1 \cdot (- 4 x)$ as $- (- 4 x)$ .

$y < - 8 - (- 4 x)$

Multiply $- 4$ by $- 1$ .

$y < - 8 + 4 x$

Rearrange terms.

$y < 4 x - 8$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 4$

$b = - 8$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $4$

y-intercept: $(0, - 8)$

Slope: $4$

y-intercept: $(0, - 8)$

Step 3

Graph a dashed line, then shade the area below the boundary line since $y$ is less than $4 x - 8$ .

$y < 4 x - 8$

Step 4

Graph 4x-y>8

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